Quadratic Equation by Rechnerzentrale

x² − 5x + 6 = 0

Coefficient a (of x²)

Must not be 0

Coefficient b (of x)

Coefficient c (constant)

Two solutions

3 and 2

x² − 5x + 6 = 0 has the solutions x₁ = 3 and x₂ = 2.

How this was calculated

D = b² − 4ac = (-5)² − 4 × 1 × 6 = 1

x = (−b ± √D) ÷ 2a = (5 ± √1) ÷ 2

x₁ = 3, x₂ = 2

Quadratic formula: if the discriminant D is positive, there are two solutions – the parabola crosses the x-axis twice.

y = x² − 5x + 6