Current for 2026As of: July 2026

Insulation Calculator calculate U-value & R-value.

Enter insulation thickness and lambda value – get instant U-value and R-value results under Germany's GEG 2024 and KfW standards

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Insulation Calculator

Calculate the U-value of a building component per DIN EN ISO 6946 – enter thickness, lambda and component type, optionally with the existing wall.

Component

1 cm40 cm
0.020 W/(m·K)0.050 W/(m·K)

Quick material selection

If provided, the total U-value of existing component + new insulation is calculated. Leave empty to assess the insulation layer only.

U-value

0.33 W/m²K

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R-value

2.86 m²K/W

GEG requirement

≤ 0.24 W/m²K

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Required thickness at λ = 0.035

  • GEG renovation (≤ 0.24)14.0 cm
  • KfW funding level (≤ 0.20)16.9 cm
  • Passive house (≤ 0.15)22.7 cm

Calculation per DIN EN ISO 6946 incl. surface resistances (Rsi/Rse per component). The GEG maximum values apply to alterations of external components on residential buildings (Annex 7 GEG 2024): external wall ≤ 0.24, roof ≤ 0.24, flat roof ≤ 0.20, components adjacent to unheated spaces ≤ 0.30 W/m²K. Without the existing component, only the insulation layer is assessed – the real component then performs better. A certified energy consultant is required for formal verification.

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U-value and insulation: formulas and GEG requirements

From λ and d to the U-value – and how much insulation is enough

The U-value (thermal transmittance) is the key metric for the thermal insulation quality of a building component. It describes how much heat energy passes through 1 m² of area per second at a temperature difference of 1 Kelvin. The calculation per DIN EN ISO 6946: U = 1 / (Rsi + d/λ + Rse), where λ is the thermal conductivity of the insulation material in W/(m·K), d is the thickness in metres and Rsi/Rse are the surface resistances (external wall: 0.13 and 0.04 m²K/W). For 10 cm of insulation with λ = 0.035: R = 0.10/0.035 = 2.86 → U = 1/(0.13 + 2.86 + 0.04) ≈ 0.33 W/(m²·K).

GEG 2024 and funding standards: Germany's Buildings Energy Act (GEG) requires U ≤ 0.24 W/(m²·K) for external walls when altering external components (renovation, Annex 7 GEG). New builds have no fixed per-component limits – compliance is verified via the reference building and primary energy demand. The KfW efficiency house funding standard usually requires U ≤ 0.20 W/(m²·K) for external walls; passive houses achieve U ≤ 0.15 W/(m²·K) or better. These values are readily achievable with 16–18 cm of EPS or mineral wool.

Thermal resistance R: The R-value is the reciprocal of the U-value: R = 1/U. It is additive: in multi-layer components, the individual resistances add up. A complete component build-up (e.g. an external wall) consists of the internal surface resistance (Rsi = 0.13 m²K/W), all material layers (render, masonry, insulation), and the external surface resistance (Rse = 0.04 m²K/W). This calculator includes the insulation layer plus surface resistances; optionally, the U-value of the existing component can be included (R supplement 1/U). For formal GEG verification, consult an energy consultant.

Cost-effectiveness of insulation: The payback period for insulation measures is typically 8–20 years, depending on energy prices, the existing condition of the building and the insulation thickness. Rule of thumb: doubling the insulation thickness halves the U-value, but saves proportionally less energy (diminishing returns). So the question is not "as much as possible" but "what is the economically optimal insulation thickness" – usually around 14–20 cm for mineral wool and 12–16 cm for PUR.

Insulation materials compared

Thermal conductivity and applications

EPS (polystyrene): 0.030–0.040
Inexpensive; ETICS facades, floor slabs; not vapour-permeable
Mineral wool: 0.032–0.045
Non-combustible; roof, wall, facade; vapour-permeable
PUR/PIR: 0.020–0.028
Best insulation performance per cm; more expensive; flat roof, facade
Wood fibre: 0.038–0.050
Ecological; buffers summer heat; more expensive
Cellulose: 0.040–0.045
Blown-in insulation; cavities, timber frame; recycled
Sheep's wool: 0.035–0.045
Ecological; good moisture regulation; for interior fit-out

Calculation examples

10 cm EPS (λ = 0.035 W/(m·K)) – reference value

10 cm EPS (λ = 0.035 W/(m·K)) – reference value
PositionBetrag
Insulation thickness10 cm = 0.10 m
Lambda (λ)0.035 W/(m·K)
R-value (d÷λ)2.857 m²K/W
+ surface resistances (external wall)Rsi 0.13 + Rse 0.04 m²K/W
U-value (1÷3.027)0.33 W/(m²·K)

GEG-compliant: 18 cm EPS for U ≤ 0.20 W/(m²·K)

GEG-compliant: 18 cm EPS for U ≤ 0.20 W/(m²·K)
PositionBetrag
Target U-value (GEG)≤ 0.20 W/(m²·K)
Lambda EPS (λ)0.032 W/(m·K)
R-value (0.18÷0.032)5.625 m²K/W
+ surface resistances (external wall)Rsi 0.13 + Rse 0.04 m²K/W
U-value (1÷5.795)0.173 W/(m²·K) ✓

Frequently asked questions about the insulation calculator

Everything about U-value, R-value, lambda and GEG requirements

The U-value (thermal transmittance) indicates how much heat passes per second through 1 m² of a building component at a temperature difference of 1 K. Unit: W/(m²·K). Per DIN EN ISO 6946: U = 1 ÷ (Rsi + d÷λ + Rse) with the surface resistances Rsi/Rse (external wall: 0.13/0.04 m²K/W). For 10 cm of insulation with λ = 0.035: R = 2.86 → U ≈ 0.33 W/(m²·K).

The R-value is the reciprocal of the U-value: R = d ÷ λ = 1 ÷ U. Unit: m²·K/W. The higher the R-value, the better the insulating effect. In multi-layer constructions, the R-values of the individual layers add up. The total resistance also includes the internal (Rsi = 0.13) and external (Rse = 0.04) surface resistances.

Germany's 2024 Buildings Energy Act (GEG) requires when altering external components (renovation, Annex 7): external wall ≤ 0.24 W/(m²·K), pitched roof and top-floor ceiling ≤ 0.24 W/(m²·K), flat roof ≤ 0.20 W/(m²·K), components adjacent to unheated spaces or soil ≤ 0.30 W/(m²·K), windows ≤ 1.3 W/(m²·K) (roof windows 1.4). New builds are instead verified via the reference building. KfW funding standard: external wall usually ≤ 0.20 W/(m²·K). Passive house: components ≤ 0.15 W/(m²·K).

With EPS (λ = 0.032 W/(m·K)): d = λ ÷ U = 0.032 ÷ 0.20 = 0.16 m = 16 cm. With mineral wool (λ = 0.035): d = 0.035 ÷ 0.20 = 17.5 cm. With PUR (λ = 0.022): d = 0.022 ÷ 0.20 = 11 cm. PUR/PIR is the slimmest solution but more expensive. Mineral wool and EPS are cheaper but need more space.

The lambda value (thermal conductivity λ) indicates how well a material conducts heat. The smaller λ, the better the insulating effect. Typical values: EPS/polystyrene 0.030–0.040 W/(m·K), mineral wool 0.032–0.045 W/(m·K), wood fibre 0.038–0.050 W/(m·K), PUR/PIR 0.020–0.028 W/(m·K), cellulose 0.040–0.045 W/(m·K). The exact value is printed on the product packaging.

Sources & calculation basis

Our calculations are based on the following official sources (as of: July 2026):

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